5.
Find the solution to the system of equations by using either graphing or substitution.
y = 6 – x and y = x – 2
(2, 4)
(–4, 2)
(4, 2)
no solutions
6.
y = 2x – 1 and y = x + 3 (1 point)(4, 7)
(7, 4)
(–7, –4)
infinite solutions
7.
y = 4x and y + x = 5
(–4, 1)
(1, 4)
(–3, 2)
(2, 3)
my answers
5. -4,2
6. 7,4
7. -4,1
To solve the system of equations, you can use either graphing or substitution.
For the first question, let's use substitution:
y = 6 - x and y = x - 2
Substituting the value of y from the first equation into the second equation, we have:
x - 2 = 6 - x
Now, solve for x:
2x = 8
x = 4
Substituting the value of x back into the first equation to find y:
y = 6 - 4 = 2
Therefore, the solution to the system is (4, 2), which matches your answer.
For the second question:
y = 2x - 1 and y = x + 3
Since the equations are already in y = form, we can directly solve them by setting them equal to each other:
2x - 1 = x + 3
Solving for x:
x = 4
Substituting the value of x back into any of the equations to find y:
y = 2(4) - 1 = 7
Therefore, the solution to the system is (4, 7), which matches your answer.
For the third question:
y = 4x and y + x = 5
We can solve this system by substitution as well. Start by solving the second equation for y:
y = 5 - x
Now, substitute this value of y into the first equation:
4x = 5 - x
5x = 5
x = 1
Substituting the value of x back into the second equation to find y:
y + 1 = 5
y = 4
Therefore, the solution to the system is (1, 4), which matches your answer.
In summary, your answers for all three questions (5. -4,2; 6. 7,4; 7. -4,1) are incorrect. The correct answers are (5. 4,2; 6. 4,7; 7. 1,4)
#5: Bzzt
plug in your values:
2 = 6-(-4)
-4 = 2-2
How about (4,2)
#6 Nope
#7 Nope
Post your work and we can show you where you went wrong. You're evidently not getting the method for solving these things. You might try reviewing your own materials first.