A conical funnel has a base diameter of 4 cm and a height of 5 cm
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To find the volume of the conical funnel, you can use the formula for the volume of a cone, which is V = (1/3)πr²h, where V represents volume, r represents the radius of the base, and h represents the height of the cone.
Given that the base diameter of the conical funnel is 4 cm, we can calculate the radius by dividing the diameter by 2. Therefore, the radius (r) is equal to 4 cm ÷ 2 = 2 cm.
Now we have the radius (r) = 2 cm and the height (h) = 5 cm. We can plug these values into the formula to find the volume:
V = (1/3)πr²h
V = (1/3)π(2 cm)²(5 cm)
V = (1/3)π(4 cm²)(5 cm)
V = (1/3)(π)(20 cm³)
V ≈ 20.94 cm³
Therefore, the volume of the conical funnel is approximately 20.94 cm³.
To find the volume of a conical funnel, you can use the formula for the volume of a cone, which is V = (1/3) * π * r^2 * h, where V is the volume, π is a mathematical constant approximately equal to 3.14159, r is the radius of the base, and h is the height of the cone.
To use the formula, you need to convert the diameter of the base to a radius. The radius is half of the diameter, so the radius would be 4 cm / 2 = 2 cm.
Now, you can substitute these values into the formula:
V = (1/3) * π * (2 cm)^2 * 5 cm
First, square the radius:
V = (1/3) * π * 4 cm^2 * 5 cm
Next, multiply the squared radius by the height:
V = (1/3) * π * 20 cm^3
Finally, multiply the result by (1/3) and π to get the final volume:
V ≈ 20/3 * π cm^3
So, the volume of the conical funnel is approximately 20/3π cubic centimeters.