the density of mercury is 13.6 g/cm3. how many liters are in 829 grams of Hg.

To determine the number of liters in 829 grams of Hg, we need to use the given density of mercury.

Density is defined as mass divided by volume (D = m/V).

In this case, the density of mercury is given as 13.6 g/cm^3.

We can rearrange the formula to solve for volume (V).

V = m/D

Substituting the values for mass (829 grams) and density (13.6 g/cm^3):

V = 829 g / 13.6 g/cm^3

To proceed with the calculation, we need to make sure the units are consistent. Since the density is given in grams per cubic centimeter, we need to convert grams to cubic centimeters.

To do this, we need to know the volume of 1 gram of mercury. We can use the fact that the density of mercury is equal to mass divided by volume.

13.6 g/cm^3 = 1 g / V

Rearranging the formula to solve for the volume:

V = 1 g / 13.6 g/cm^3

V ≈ 0.0735 cm^3

Now we can continue with the original calculation:

V = 829 g / 13.6 g/cm^3

V ≈ 829 g * (1 cm^3 / 13.6 g)

V ≈ 60.956 cm^3

Since we want to express the volume in liters, we need to convert cubic centimeters to liters.

1 cm^3 = 1 mL = 0.001 L

V ≈ 60.956 cm^3 * (0.001 L / 1 cm^3)

V ≈ 0.060956 L

Therefore, there are approximately 0.060956 liters in 829 grams of mercury (Hg).