# math

f(x)= x^2/√x^2 + 1

I have no clue.

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1. You have defined the function f(x), but not asked a question. Your writing of the equation is unclear about whether x^2 +1 is all under the square root sign and in the denominator.

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posted by drwls
2. Oh, sorry.

I have to know whether it is even, odd, or neither.

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3. Even because it satisfy f(x) = f(-x). In order words, symmetrical about the y axis.

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4. If sqrt (x^2 +1) is the denominator, and if the positive square root is intended, then f(x) = f(-x), so the function is even.

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posted by drwls

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