Movie tickets are $7 for students and $9 for adults. A group of 8 people spent $66 on movie tickets. How many adult tickets were bought?
adult tickets --- x
student tickets --- 8-x
solve for x
9x + 7(8-x) = 66
9 x 5 adults + 7 (8-5)= 66
45 + 7 (3)kids = 66
45 + 21 = 66
Now I found 5 adults by multiplying 9 x 5=45 just because that's the only way I know... Now I have no idea how to find x other than that. I am trying to help my 3rd grader with that. Please help.
You can take the 8 people and start by subtracting out 2 students. X that by the cost of the student ticket then take the 6 left from the 8 people and X that by the cost of the adult ticket. This you will find is to much spent. Next, you can take the 8 people and use the next number(3) X that by the cost of the student ticket then take the 5 left from the 8 people and X it by the cost of the adult ticket and you will see that this equals the $66.00 total spent. So this shows that 3 student tickets and 5 adult tickets were bought for the total of $66.00.
To find the number of adult tickets bought, we can use algebraic thinking. Let's assume that 'x' represents the number of adult tickets bought. Since there were 8 people in total, the number of student tickets bought would be (8 - x).
Now, let's calculate the cost of the adult tickets. Each adult ticket costs $9, so the total cost of adult tickets would be 9x dollars.
Similarly, the cost of the student tickets can be calculated. Each student ticket costs $7, so the total cost of student tickets would be 7(8 - x) dollars.
Since the group spent a total of $66 on movie tickets, we can set up an equation:
9x + 7(8 - x) = 66
To solve this equation, we need to distribute 7 to both terms in the parentheses:
9x + 56 - 7x = 66
Combine like terms:
2x + 56 = 66
Subtract 56 from both sides:
2x = 10
Divide both sides by 2:
x = 5
Therefore, 5 adult tickets were bought.