Calculus

A particle moves along the curve y = sqr(1+x^3). As it reaches the point (2,3), the y-coordinate is increasing at a rate of 4 cm/s. How fast is the x-coordinate of the point changing at that instant.

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  1. y = √(1+x^3)
    dy/dt = 3x^2 / 2√(1+x^3) dx/dt
    4 = 3*4 / 2*3 dx/dt
    dx/dt = 2

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