im so confused about this question
Calculate the pH of a solution that has [H3O+] = 5.5 x 10-3.
pH = -log(H3O^+)
pH = -log(5.5E-3)
pH = -(-2.26)
pH = +2.26
To calculate the pH of a solution, you need to use the equation:
pH = -log[H3O+]
In this equation, [H3O+] is the concentration of hydronium ions in the solution.
Given that [H3O+] = 5.5 x 10^-3, you can substitute this value into the equation and calculate the pH as follows:
pH = -log(5.5 x 10^-3)
To evaluate this, you can take the logarithm of the concentration using the logarithm function on a calculator. Follow these steps:
1. Open a calculator.
2. Enter the value of 5.5 x 10^-3.
3. Press the "log" or "log10" button on your calculator. This will give you the logarithm of the concentration.
4. Multiply the result by -1 to get the negative value.
5. The value you get is the pH of the solution.
For example, if you enter 5.5 x 10^-3 into the calculator, the result of the logarithm should be approximately -2.26. Multiplying this value by -1 gives us 2.26. Therefore, the pH of the solution is 2.26.