im so confused about this question

Calculate the pH of a solution that has [H3O+] = 5.5 x 10-3.

pH = -log(H3O^+)

pH = -log(5.5E-3)
pH = -(-2.26)
pH = +2.26

To calculate the pH of a solution, you need to use the equation:

pH = -log[H3O+]

In this equation, [H3O+] is the concentration of hydronium ions in the solution.

Given that [H3O+] = 5.5 x 10^-3, you can substitute this value into the equation and calculate the pH as follows:

pH = -log(5.5 x 10^-3)

To evaluate this, you can take the logarithm of the concentration using the logarithm function on a calculator. Follow these steps:

1. Open a calculator.
2. Enter the value of 5.5 x 10^-3.
3. Press the "log" or "log10" button on your calculator. This will give you the logarithm of the concentration.
4. Multiply the result by -1 to get the negative value.
5. The value you get is the pH of the solution.

For example, if you enter 5.5 x 10^-3 into the calculator, the result of the logarithm should be approximately -2.26. Multiplying this value by -1 gives us 2.26. Therefore, the pH of the solution is 2.26.