One of the concrete pillars that support a house is 2.1 m tall and has a radius of 0.35 m. The density of concrete is about 2.2 103 kg/m3. Find the weight of this pillar in pounds (1 N = 0.2248 lb).

V=pi*r^2 * h=3.14*0.35^2 * 2.1=0.8o8 m^3

Mass = 0.808 m^3 * 2200kg/m*3=1777.1 kg.

Wt. = 1777.1kg * 1Lb/0.454kg = 3914 Lbs.

To find the weight of the concrete pillar in pounds, we need to follow a series of steps:

Step 1: Calculate the volume of the concrete pillar.
The volume of a cylinder can be calculated using the formula: V = π * r^2 * h, where r is the radius of the cylinder and h is the height or length of the cylinder. In this case, the radius (r) is 0.35 m and the height (h) is 2.1 m.

V = π * (0.35 m)^2 * 2.1 m

Step 2: Convert the volume from cubic meters (m^3) to cubic centimeters (cm^3) for consistency.
1 m^3 is equal to 1,000,000 cm^3. So, we can use this conversion factor to convert cubic meters to cubic centimeters.

Volume_in_cm^3 = V * 1,000,000 cm^3/m^3

Step 3: Calculate the mass of the concrete pillar.
The mass of an object can be calculated by multiplying its volume by its density. In this case, the density of concrete is given as 2.2 * 10^3 kg/m^3.

Mass = Volume_in_cm^3 * (Density_in_kg/m^3 / 1,000,000 cm^3/m^3)

Step 4: Convert the mass from kilograms (kg) to pounds (lb).
We know that 1 N (Newton) is equal to 0.2248 lb.

Weight_in_lb = Mass * (1 N / 0.2248 lb)

By following these steps, we can find the weight of the concrete pillar in pounds.