Math

Sin(30)=5/c

I don't get how to solve.... do you do

5= Sin(30)c? Then what?

  1. 👍 0
  2. 👎 0
  3. 👁 61
  1. Hahaha really helpful ;/.

    Anyways I would draw the triangle which is a 30, 60, 90 triangle. 5 is the leg opposite of 30 degrees. The hypotenuse which is c is always 2 times larger than the leg opposite of the 30 degrees in a 30, 60, 90 triangle. So the hypotenuse, c, is 10

    Or you can draw a basic 30, 60, 90 triangle. The leg opposite of 30 is 1, opposite of 60 sqrt(3) and hypotenuse is 2. Taking the sin(30) is taking the length of the leg opposite of the 30 angle and dividing it by the length of the hypotenuse. Which is 1/2. So sin(30) is 1/2 and the your equation becomes:
    5 = c/2
    c = 10.

    I believe there are other methods but I think I forgot them *shrug*.

    1. 👍 0
    2. 👎 0
  2. thank you so much!!!

    1. 👍 0
    2. 👎 0
  3. You're very welcome.

    1. 👍 0
    2. 👎 0

Respond to this Question

First Name

Your Response

Similar Questions

  1. TRIG!

    Posted by hayden on Monday, February 23, 2009 at 4:05pm. sin^6 x + cos^6 x=1 - (3/4)sin^2 2x work on one side only! Responses Trig please help! - Reiny, Monday, February 23, 2009 at 4:27pm LS looks like the sum of cubes sin^6 x +

    asked by hayden on February 23, 2009
  2. Trigonometry

    Solve the equation for solutions in the interval 0

    asked by Renee on March 7, 2016
  3. tigonometry

    expres the following as sums and differences of sines or cosines cos8t * sin2t sin(a+b) = sin(a)cos(b) + cos(a)sin(b) replacing by by -b and using that cos(-b)= cos(b) sin(-b)= -sin(b) gives: sin(a-b) = sin(a)cos(b) - cos(a)sin(b)

    asked by Pablo on November 26, 2006
  4. Calculus

    Consider the function f(x)=sin(1/x) Find a sequence of x-values that approach 0 such that (1) sin (1/x)=0 {Hint: Use the fact that sin(pi) = sin(2pi)=sin(3pi)=...=sin(npi)=0} (2) sin (1/x)=1 {Hint: Use the fact that sin(npi)/2)=1

    asked by George on September 9, 2008
  5. Calculus

    Consider the function f(x)=sin(1/x) Find a sequence of x-values that approach 0 such that (1) sin (1/x)=0 {Hint: Use the fact that sin(pi) = sin(2pi)=sin(3pi)=...=sin(npi)=0} (2) sin (1/x)=1 {Hint: Use the fact that sin(npi)/2)=1

    asked by George on September 9, 2008
  6. algebra

    Can someone please help me do this problem? That would be great! Simplify the expression: sin theta + cos theta * cot theta I'll use A for theta. Cot A = sin A / cos A Therefore: sin A + (cos A * sin A / cos A) = sin A + sin A = 2

    asked by Valerie on February 18, 2007
  7. Calculus

    Use a Riemann sum with n = 3 terms and the right endpoint rule to approx. ∫(1, 2) sin(1/x)dx. My teacher just needs the terms written out, no need to add or multiply. This is a problem she did up on the board, so here's her

    asked by Justin on November 4, 2015
  8. Calculus

    Consider the function f(x)=sin(1/x) Find a sequence of x-values that approach 0 such that sin (1/x)=0 sin (1/x)=1 sin (1/x)=-1 Is sin sin (1/x)=0 and sin (1/x)=-1 does not exist. What is sin (1/x)=1 then.

    asked by George on September 8, 2008
  9. Maths

    Question : Integrate [x/(1+(sin a*sin x))] from 0 to pi My first thought was to apply integrate f(x) dx= f(a-x) dx method Which simplified the integral into; 2I = integrate [pi/(1+(sin a*sin x))] dx , cancelling out x Then I made

    asked by Ashley on March 18, 2019
  10. math

    Prove that for all real values of a, b, t (theta): (a * cos t + b * sin t)^2

    asked by mathstudent on December 19, 2006
  11. Calculus

    I need to find the exact solutions on the interval [0,2pi) for: 2sin^2(x/2) - 3sin(x/2) + 1 = 0 I would start: (2sin(x/2)-1)(sin(x/2)-1) = 0 sin(x/2)=1/2 and sin(x/2)=1 what's next? Ok, what angle has a sin equal to say 1/2 sin

    asked by Jen on August 21, 2006

More Similar Questions