a stone of mass 50g is being rotated in a circle of radius 50cm with a uniform speed of 2m/s.what is thje accelerationof the stone?

To find the acceleration of the stone being rotated in a circle, we can use the formula for centripetal acceleration:

a = v^2 / r

where:
a is the centripetal acceleration
v is the velocity (uniform speed)
r is the radius of the circle

Given:
Mass of the stone (m) = 50g = 0.05 kg (converting from grams to kilograms)
Radius of the circle (r) = 50 cm = 0.5 m (converting from centimeters to meters)
Velocity (v) = 2 m/s

Substituting the given values into the formula, we have:

a = (2 m/s)^2 / 0.5 m
a = 4 m^2/s^2 / 0.5 m
a = 8 m/s^2

Therefore, the acceleration of the stone is 8 m/s^2.

centripetal acceleration

a= mv²/R=
=0.05•4/0.5=0.4 m/s²

centripetal acceleration

a= v²/R=
= 4/0.5=8 m/s²
centripetal force
F= mv²/R=
=0.05•4/0.5=0.4 m/s²