How do I solve these for x?
1) 1+2log5x=7
2) logaX=3/2loga9+loga2
1.
is that ... 2log (5x) or is it ... 2log5x ?
2. I will assume that 'a' is the base
logax = loga(9^(3/2)) + loga2
logax = loga27 + loga2
logax = loga((27)(2))
x = 54