what mass of 25% ba(n03)2 solution contain 40 grams of ba(n03)2 ?

Answer 160g

My calculation
40g/261.37g/mol = 0.15305/0.25g = 0.612
This answer is not right

Who helps

You can solve this problem by using the concept of mass percentage. To find the mass of the 25% Ba(NO3)2 solution that contains 40 grams of Ba(NO3)2, you can set up a proportion using the mass percentage formula:

Mass of solute / Mass of solution = Mass percentage

Let's denote the mass of the Ba(NO3)2 solution as "x" (in grams):

40g (Ba(NO3)2) / x (solution) = 0.25 (25%)

To solve for x, we can cross-multiply and divide:

40g * 100 / 0.25 = x

x ≈ 160g

Therefore, the mass of the 25% Ba(NO3)2 solution that contains 40 grams of Ba(NO3)2 is approximately 160 grams.