# Algebra

real/imaginary solutions
x^(2/3)+3x^(1/3)-10=0

u=x^(1/3) u^2=(x^(1/3)^2=x^(2/3)
u^2+3u-10=0
(u+5)(u-2)
u=-5 u=2
x^(1/3)=-5 x^(1/3)=2
(x^(1/3)^3=-5^3(x^(1/3)^3=2^3
x=-125 or x=8

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posted by Reiny

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