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52*10E-10Kg
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-15 + 4/5( 15e - 10) - 10e
−15+45(15e−10)−10e.(1 point)
Responses
−15+4/5(15e−10)−10e.
-15+4/5(15e-10)-10e
-15 + 4/5(15e - 10) - 10e
simplify-15 + (4/5)(15e-10) - 10e
at what height above the ground must a body of mass 10kg be situated in order to have potential energy equal in value to the
-15+4/5(15e-10)-10e.
−15+4/5(15e−10)−10e
- 15 + 4/5 * (15e - 10) - 10e (1 point)
2e - 23 2e + 23 O - 2e + 23 - 2e - 23
