acetaldehyde Ch3Cho will decomposed into methane and CO according to
Ch3Cho->ch4+Co
at 450 C the rate consumption of Ch3cho is measured to vary with the concentrate of heliumCh3Cho raised to the power 1.5
with a Ch3Cho concentrate of 0.222 M ,the rate of consumption of consumption Ch3Cho at 450C is measured to be 3.33*10^-3 m/s.calculate the sludge of production of production of CO When concentrate of Ch3Cho has fallen to 0.111 M
answer in M/S
1.18e-3
To solve this problem, we can use the rate equation given: Rate = k * [Ch3Cho]^1.5
We are given that at a Ch3Cho concentration of 0.222 M, the rate of consumption is 3.33 * 10^-3 m/s. Let's plug in these values and solve for the rate constant, k:
3.33 * 10^-3 m/s = k * (0.222 M)^1.5
Now we can solve for k:
k = (3.33 * 10^-3 m/s) / (0.222 M)^1.5
Next, we need to calculate the rate of consumption of Ch3Cho when the concentration has fallen to 0.111 M. We can plug this new concentration into the rate equation:
Rate = k * (0.111 M)^1.5
Now, let's calculate the rate:
Rate = k * (0.111 M)^1.5
Rate = k * 0.019176
Finally, we can use the rate equation to calculate the production rate of CO when the Ch3Cho concentration has fallen to 0.111 M:
Production rate of CO = Rate * 1 mol Ch3Cho / 1 mol CO
Keep in mind that the stoichiometric ratio of Ch3Cho to CO is 1:1. Therefore, the production rate of CO is equal to the rate calculated above.
Hope this helps!