o prepare a 200 mL of aqueous stock solution X, you transferred 50 mL of a known concentration solution into a 200 mL volumetric flask. If you realize that the volumetric flask was contaminated with water droplets after you cleanly transferred the known concentration solution. The 200 mL solution X will have a?
(higher, lower or same) concentration than(as) you originally calculated.
Let's see. We transfer 50 mL of a known concn into a 200 mL volumetric flask. The 200 mL flask already contained some water in it. Then you added water to fill to the mark in the 200 mL volumetric flask. What difference does it make how much water was in the flask (at least as long as the amount of water was less than 200-50)? Extra water was just extra water. What matters is that the final volume was 200 you used 50 mL of stock solution to start, so you have diluted it 50 to 200.
To determine the effect of the water droplets on the final concentration of solution X, we need to consider the dilution factor involved in transferring the known concentration solution.
When you transferred 50 mL of the known concentration solution into the 200 mL volumetric flask, you effectively diluted the solution by a factor of 4 (200 mL / 50 mL = 4).
Now, if water droplets were to contaminate the flask after transferring the known concentration solution, the total volume in the flask would increase due to the added water droplets. Let's say the volume of water droplets that contaminated the flask is V mL. In this case, the final volume of solution X would be 200 mL + V mL.
However, since the initial 50 mL of known concentration solution is still present in the flask, the volume of the known concentration solution remains unchanged.
Therefore, the dilution factor remains the same at 4 (200 mL + V mL) / (50 mL) = 4.
Now, let's consider concentrations. If the initial concentration of the known solution was C1, then the final concentration of solution X would be calculated by dividing the initial concentration by the dilution factor (C1 / 4).
To summarize:
- The dilution factor remains unchanged at 4.
- The initial concentration of the known solution remains unchanged.
- Therefore, the final concentration of solution X will be the same as you originally calculated, regardless of the water droplet contamination in the flask.