I need to find the symmetry of a polynomial function graph. Is this correct?
f(x)=x^2+2x-1
x=-6/2x=-2/2*1
x=-2/2=-1
It is symmetric about x=-1/-2
So I'm a bit confused to what you have done >.<.. To find the symmetry for a trinomial it is 2ax + b = 0. So you'll have to use this equation and solve for x. If you haven't learned this equation yet, a is the coefficient of x^2 and b is the coefficient of x.
Oh NVM, I see what you did now >.<. You were correct up to x=-2/2=-1. However, your answer is x = -1/-2(which is 1/2)? How did x go from -1 to 1/2 xD?
My answer is suppose to be x= -1/2. Is that correct?
To determine the symmetry of a polynomial function graph, you need to identify the axis of symmetry. The axis of symmetry is a vertical line that divides the graph into two equal halves.
To find the axis of symmetry, you can use the formula x = -b/2a, where a, b, and c are the coefficients of the quadratic polynomial function in the form ax^2 + bx + c.
For the given function f(x) = x^2 + 2x - 1, the coefficients are a = 1, b = 2, and c = -1.
Using the formula, you have:
x = -(2)/(2*1)
Simplifying further:
x = -2/2
x = -1
Therefore, the axis of symmetry for the graph of the function f(x) = x^2 + 2x - 1 is x = -1.
The graph is symmetric about the line x = -1. This means that if you fold the graph along the line x = -1, the two halves of the graph will perfectly overlap.