IF the speed of train A is 10 mph slower than train B. Train A travels 220 miles in the same time it takes train B to travel 270. What is the speed of both trains.
speed of train A --- x
speed of train B ---- x+10
time for A's trip = 220/x
time for B's trip = 270/(x+10)
220/x = 270/(x+10)
270x = 220x + 2200
50x = 2200
x = 44
take it from here.
To find the speed of both trains, let's assume the speed of train B as 'x' mph. Train A is stated to be 10 mph slower than train B, so the speed of train A would be 'x - 10' mph.
We are given that train A travels 220 miles in the same time it takes train B to travel 270 miles. We can use the formula time = distance / speed to calculate the time taken for both trains:
For Train A: time taken = 220 miles / (x - 10) mph
For Train B: time taken = 270 miles / x mph
Since both trains are taking the same time, we can set up an equation:
220 / (x - 10) = 270 / x
To solve this equation, we can cross-multiply:
220x = 270(x - 10)
220x = 270x - 2700
270x - 220x = 2700
50x = 2700
x = 54
So, the speed of Train B (x) is 54 mph, and the speed of Train A (x - 10) is 54 - 10 = 44 mph.