I toss a coin 4 times. Find the chance of getting the sequence HTHT
the chance of getting any particular sequence of 4 throws is (1/2)^4 = 1/16
There are 16 possible sequences; the named one is just 1 of the 16
Thank you :)
Well, the chance of getting a "H" or "T" on any given coin flip is 50%. So if we assume each coin flip is independent, meaning the outcome of one flip doesn't influence the outcome of another flip, then the chance of getting the sequence HTHT would be (0.5)^4, which equals 0.0625 or 6.25%.
But hey, remember, even if the odds might be against you, life is full of surprises! So keep flipping those coins and who knows, maybe you'll end up with HTHT! Or maybe you'll end up with something even more unexpected, like a kangaroo hopping by with a lucky four-leaf clover in its pouch. Anything is possible!
To find the chance of getting the sequence HTHT when tossing a coin 4 times, we need to calculate the probability of each individual toss and then multiply them together.
Assuming a fair coin, the probability of getting a heads (H) or tails (T) on a single toss is both 1/2 (0.5).
Since we have 4 tosses, the probability of getting HTHT can be calculated as follows:
Probability of getting H on the first toss = 1/2 (0.5)
Probability of getting T on the second toss = 1/2 (0.5)
Probability of getting H on the third toss = 1/2 (0.5)
Probability of getting T on the fourth toss = 1/2 (0.5)
To find the overall probability, we multiply the individual probabilities:
(1/2) * (1/2) * (1/2) * (1/2) = 1/16 (0.0625)
Therefore, the chance of getting the sequence HTHT when tossing a coin 4 times is 1/16 or 0.0625, which is equal to 6.25%.