Calculate the H3O concentration if 100.0 ml of the .10M HNO3 solution is diluted to 1.0L with water?
0.10M HNO3 x (100/1000) = ?
0.01M? Is is really that simple, or did I mess up?
It really is that simple. I prefer to use the dilution formula as
c1v1 = c2v2 where
c = concn
v = volume
and that works when volume is other than mL (as long as the units for v1 and v2 are the same) and c1 and c2 can be concentrations other than molarity.
To calculate the H3O+ concentration in a dilution, you need to use the concept of dilution and the initial concentration of the solution.
Dilution is a process in which a solute (in this case, HNO3) is added to a solvent (water) to decrease the concentration. The equation for dilution is:
C1V1 = C2V2
Where C1 and V1 are the initial concentration and volume, and C2 and V2 are the final concentration and volume.
Let's calculate the final concentration of the H3O+ ions using the given information using the dilution equation:
C1 = 0.10 M (initial concentration of HNO3)
V1 = 100.0 ml (volume of the initial solution)
C2 = ? (final concentration of H3O+ ions)
V2 = 1000.0 ml (volume of the final solution after dilution)
First, we convert the mL to L:
V1 = 100.0 ml = 0.100 L
V2 = 1000.0 ml = 1.000 L
Now, plug the values into the dilution equation:
(0.10 M)(0.100 L) = C2(1.000 L)
0.010 mol = C2(1.000 L)
C2 = 0.010 M
So, the final concentration of H3O+ ions in the solution is 0.010 M.