if you dissolve 350 g of K(2)CrO(4)in 2.4 kg of water, what is the molality of the solution?
Molality is found by dividing the moles of solute (K2CrO4) by the Kg of of solvent (H2O).
So first convert g K2CrO4 to moles.
Molecular weight of K2CrO4= 194.19
So 350g/194.19g= 1.8024 moles.
Then 1.8024 moles K2CrO4/ 2.4 kg H2O=
.751 moles/ kg
Hope that helps!
Oh, chemistry, bringing back fond memories of failed experiments and explosive mishaps! Now, let's tackle your question.
To find the molality of the solution, we need to remember that molality (m) is calculated by dividing the moles of solute by the mass of the solvent (in kilograms).
First, let's convert the mass of the solute, K(2)CrO(4), into moles. Just for fun, let's say that K(2)CrO(4) stands for "Keep 2 clowns Representing Oxygen." With a molar mass of 294.18 g/mol, we divide 350 g by 294.18 g/mol to get approximately 1.19 mol.
Next, we need to convert the mass of the solvent, water, to kilograms. Lucky for us, there are 1000 grams in a kilogram. So, 2.4 kg is the same as 2400 g.
Finally, we can calculate the molality by dividing the moles of solute by the mass of the solvent in kilograms. So, 1.19 mol divided by 2.4 kg gives us an approximate molality of 0.50 mol/kg.
Voilà! The molality of the solution is approximately 0.50 mol/kg. Keep in mind, though, that I'm a clown bot, not a chemistry professor. So, please double-check these calculations with your textbooks or consult a real expert.
To find the molality of the solution, we first need to calculate the number of moles of K2CrO4 and the mass of the water.
1. Calculate the number of moles of K2CrO4:
Molar mass of K2CrO4 = (2 * Atomic mass of K) + Atomic mass of Cr + (4 * Atomic mass of O)
= (2 * 39.10 g/mol) + 52.00 g/mol + (4 * 16.00 g/mol)
= 194.19 g/mol
Number of moles of K2CrO4 = Mass / Molar mass
= 350 g / 194.19 g/mol
≈ 1.801 mol
2. Calculate the mass of water:
Mass of water = 2.4 kg = 2400 g
3. Calculate the molality:
Molality (m) = Number of moles of solute / Mass of solvent in kg
= 1.801 mol / 2.4 kg
≈ 0.751 mol/kg
Therefore, the molality of the solution is approximately 0.751 mol/kg.
To find the molality of a solution, we need to know the amount of solute (in moles) and the mass of the solvent (in kilograms).
1. Calculate the moles of K2CrO4:
First, we need to determine the molar mass of K2CrO4.
Molar mass of K: 39.10 g/mol
Molar mass of Cr: 52.00 g/mol
Molar mass of O: 16.00 g/mol
So, the molar mass of K2CrO4 = (2 * 39.10 g/mol) + 52.00 g/mol + (4 * 16.00 g/mol) = 194.20 g/mol
Next, we need to convert the mass of K2CrO4 to moles:
moles of K2CrO4 = (mass of K2CrO4) / (molar mass of K2CrO4)
moles of K2CrO4 = 350 g / 194.20 g/mol = 1.802 mol
2. Calculate the mass of water in kilograms:
Given, mass of water = 2.4 kg
3. Calculate the molality of the solution:
Molality (m) = (moles of solute) / (mass of solvent in kg)
Molality (m) = 1.802 mol / 2.4 kg = 0.751 mol/kg
Therefore, the molality of the solution is 0.751 mol/kg.