interpret the following balanced equation into Particles, Moles, Mass:

2Al+3CuSO4== AL2(SO4)3+ 3Cu

mols:

2 mol Al + 3 mols CuSO4 --> etc.
mass:
2*atomic mass Al + 3*molar mass CuSO4 ==> etc.

The balanced equation 2Al + 3CuSO4 → Al2(SO4)3 + 3Cu can be interpreted in terms of particles, moles, and mass as follows:

Particles:
2 moles of Aluminum (Al) react with 3 moles of Copper(II) sulfate (CuSO4) to produce 1 mole of Aluminum sulfate (Al2(SO4)3) and 3 moles of Copper (Cu).

Moles:
The equation shows that 2 moles of Aluminum react with 3 moles of Copper(II) sulfate to produce 1 mole of Aluminum sulfate and 3 moles of Copper.

Mass:
To determine the mass calculations, you need to know the molar mass of each substance involved in the reaction. The molar mass of Aluminum (Al) is 26.98 g/mol, Copper(II) sulfate (CuSO4) is 159.6 g/mol, and Aluminum sulfate (Al2(SO4)3) is 342.15 g/mol.

Using this information, you can calculate the mass involved in the reaction. For example, if you have 2 moles of Aluminum (Al), the mass would be 2 moles Al x 26.98 g/mol Al = 53.96 grams of Aluminum.

Similarly, you can calculate the mass for the other substances involved in the reaction based on their respective moles and molar masses.

To interpret the given balanced equation into particles, moles, and mass, we'll need to understand the stoichiometry of the equation. Let's break it down step by step:

Balanced equation: 2Al + 3CuSO4 → Al2(SO4)3 + 3Cu

1. Particles: The coefficients in the balanced equation represent the number of particles involved in the reaction.

- 2Al means there are 2 aluminum atoms involved.
- 3CuSO4 means there are 3 copper(II) sulfate molecules, each containing 1 copper atom (Cu), 1 sulfur atom (S), and 4 oxygen atoms (O).
- Al2(SO4)3 means there are 2 aluminum ions (Al3+) and 3 sulfate ions (SO42-).
- 3Cu means there are 3 copper atoms involved.

2. Moles: To convert from particles to moles, we need to use Avogadro's number, which states that 1 mole of any substance contains 6.022 × 10^23 particles.

- 2Al represents 2 moles of aluminum (Al).
- 3CuSO4 represents 3 moles of copper(II) sulfate (CuSO4).
- Al2(SO4)3 represents 1 mole of aluminum sulfate (Al2(SO4)3).
- 3Cu represents 3 moles of copper (Cu).

3. Mass: To determine the mass, we need to know the molar mass of each substance involved in the reaction.

- The molar mass of aluminum (Al) is 26.98 g/mol.
- The molar mass of copper(II) sulfate (CuSO4) is 159.62 g/mol.
- The molar mass of aluminum sulfate (Al2(SO4)3) is 342.15 g/mol.
- The molar mass of copper (Cu) is 63.55 g/mol.

Using the coefficients in the balanced equation, we can calculate the mass of each substance involved:

- For aluminum:
Moles of Al = 2
Mass of Al = Moles of Al × Molar mass of Al = 2 × 26.98 g/mol

- For copper(II) sulfate:
Moles of CuSO4 = 3
Mass of CuSO4 = Moles of CuSO4 × Molar mass of CuSO4 = 3 × 159.62 g/mol

- For aluminum sulfate:
Moles of Al2(SO4)3 = 1
Mass of Al2(SO4)3 = Moles of Al2(SO4)3 × Molar mass of Al2(SO4)3 = 1 × 342.15 g/mol

- For copper:
Moles of Cu = 3
Mass of Cu = Moles of Cu × Molar mass of Cu = 3 × 63.55 g/mol

By performing the calculations, you will find the respective masses for each substance involved in the equation.