3) A shell is fired from ground level with a muzzle speed of 350 ft / s and elevation and angle
of 60 . Find
(a) parametric equation for the shell’s trajectory
(b) the maximum height reached by the shell
(c) the horizontal distance traveled by the shell
(d) the speed of the shell at impact.
Vo = 350Ft/s[60o].
Xo = 350*cos60 = 175 Ft/s
Yo = 350*sin60 = 303 Ft/s.
b. Y^2 = Yo^2 + 2g*h
h = (Y^2-Yo^2)/2g
h = (0-(303)^2)/-64 = 1435 Ft.
c. Dx = Vo^2*sin(2A)/g
Dx = (350)^2*sin(120)/32 = 3315 Ft.
d. 350 Ft/s[60o]. Same as initial velocity.
posted by Henry