You work with the following system:
2X(g) <---> Y(g)
At, equilibrium, [Y]=3[X]. If K=10, calculate the [Y] at equilibrium.
K = (Y)/(X)^2
10 = (3X)/(X)^2
10 = 3X/X^2
Solve for X and convert to Y.
how do u convert for y?
To calculate the concentration of Y at equilibrium, we can use the equilibrium expression and the given information about the equilibrium constant.
The equilibrium expression for the given system is:
K = [Y] / [X]^2
We know that at equilibrium, [Y] = 3[X]. By substituting this into the equilibrium expression, we get:
K = (3[X]) / [X]^2
Simplifying this equation, we have:
K = 3 / [X]
Now, we can rearrange the equation to solve for [X]:
[X] = 3 / K
Substituting the value of K (given as 10), we can calculate the concentration of X at equilibrium:
[X] = 3 / 10 = 0.3
Since the stoichiometric ratio for Y with respect to X is 1:3, we can calculate the concentration of Y at equilibrium by multiplying the concentration of X by 3:
[Y] = 3 * [X] = 3 * 0.3 = 0.9
Therefore, the concentration of Y at equilibrium is 0.9.