during landing the leg is subjected to a vertical load of 10,000N, and a drag load 3000N,

To understand the total load on the leg during landing, we need to consider both the vertical and drag loads.

1. Vertical Load: The vertical load represents the downward force that is acting on the leg. In this case, the vertical load is given as 10,000 N.

2. Drag Load: The drag load represents the force acting in the opposite direction of the motion, parallel to the ground. In this case, the drag load is given as 3,000 N.

To find the total load on the leg, we need to determine the resultant of these two loads. This can be done using vector addition.

To perform vector addition, we can use the Pythagorean theorem and the law of cosines. The Pythagorean theorem helps us find the magnitude of the resultant, while the law of cosines helps us find the angle between the resultant and the vertical load.

Let's assume the angle between the resultant and the vertical load is θ.

Using the Pythagorean theorem:
Resultant magnitude^2 = vertical load^2 + drag load^2

Substituting the given values:
Resultant magnitude^2 = (10,000 N)^2 + (3,000 N)^2

Now, we can solve for the magnitude of the resultant:
Resultant magnitude = √[(10,000 N)^2 + (3,000 N)^2]

To find the angle θ, we can use the law of cosines:
cos(θ) = (vertical load^2 + resultant^2 - drag load^2) / (2 * vertical load * resultant)

Substituting the given values:
cos(θ) = (10,000 N^2 + (Resultant magnitude)^2 - 3,000 N^2) / (2 * 10,000 N * Resultant magnitude)

Finally, to find the angle between the resultant and the vertical load, we can take the inverse cosine (arccos) of cos(θ):
θ = arccos(cos(θ))

By using this method, you can calculate both the magnitude and angle of the total load on the leg during landing.