a car moving at 4.5 m/s accelerates at 2.5 m/s2. How far will it be moving after 7 seconds.
d = Vo*t + 0.5a*t^2
d = 4.5*7 + 0.5*2.5*7^2 = 92.75 m.
To find the distance the car will be moving after 7 seconds, we need to use the equation of motion that relates speed, acceleration, and time.
The equation we'll use is:
Distance = Initial Speed × Time + (1/2) × Acceleration × Time²
Given information:
Initial speed (u) = 4.5 m/s
Acceleration (a) = 2.5 m/s²
Time (t) = 7 seconds
Plugging in the values into the equation, we get:
Distance = (4.5 m/s) × (7 s) + (1/2) × (2.5 m/s²) × (7 s)²
Simplifying the equation:
Distance = 4.5 m/s × 7 s + 0.5 × 2.5 m/s² × 7 s × 7 s
Distance = 31.5 m + 17.5 m
Distance = 49 m
Therefore, the car will be moving 49 meters after 7 seconds.