how many milliliter of .750M sulfuric acid are needed to neutralize completely 20 g of NaOH?

H2SO4 + 2NaOH ==> Na2SO4 + 2H2O

mols NaOH = grams/molar mass
Using the coefficients in the balanced equation convert mols NaOH to mols H2SO4.
Then M H2SO4 = mols H2SO4/L H2SO4.

1333.33

To find out how many milliliters of 0.750M sulfuric acid are needed to neutralize 20 g of NaOH, we will use the concept of stoichiometry. Here's how you can proceed:

1. Start by determining the molar mass of NaOH (Sodium Hydroxide). The molar mass of Na is approximately 23 g/mol, the molar mass of O is approximately 16 g/mol, and the molar mass of H is approximately 1 g/mol. Therefore, the molar mass of NaOH is 23 + 16 + 1 = 40 g/mol.

2. Calculate the number of moles of NaOH using the given mass and molar mass. The number of moles can be calculated using the formula: moles = mass / molar mass. Substitute the given values: moles = 20 g / 40 g/mol = 0.5 moles.

3. Now, let's use the balanced chemical equation between sulfuric acid (H2SO4) and sodium hydroxide (NaOH) to determine the stoichiometric ratio. The balanced equation is as follows:

H2SO4 + 2NaOH → Na2SO4 + 2H2O

From the equation, we can see that 1 mole of sulfuric acid reacts with 2 moles of sodium hydroxide. Therefore, the stoichiometric ratio is 1:2.

4. Given that the concentration of sulfuric acid is 0.750M, we know that there are 0.750 moles of sulfuric acid in 1 liter of solution.

5. To find the number of moles of sulfuric acid needed to neutralize the NaOH, we can use the stoichiometry. Since the stoichiometric ratio is 1:2, we can multiply the number of moles of NaOH by 0.750 to get the moles of sulfuric acid required. Therefore, moles of sulfuric acid = 0.5 moles NaOH * 0.750 = 0.375 moles.

6. Finally, we can calculate the volume of sulfuric acid solution needed in milliliters by using the molarity formula: Molarity = moles / volume (in liters). Rearranging the formula, volume (in liters) = moles / Molarity. Substituting the values, we get the volume (in liters) = 0.375 moles / 0.750 mol/L = 0.5 L.

7. To convert liters to milliliters, multiply the volume (in liters) by 1000. Therefore, volume (in milliliters) = 0.5 L * 1000 = 500 mL.

So, 500 milliliters of 0.750M sulfuric acid are needed to completely neutralize 20 g of NaOH.