2.0kg block of iron transfers 180,000j to the atmosphere around it. If its initial temperature was 350 celius what is it's final temperature?
If you know the specific heat of iron, you can use Q = mc(delta T).
To find the final temperature of the iron block, we can use the specific heat capacity formula:
Q = mc(delta T)
Where:
Q = amount of heat transferred (in Joules)
m = mass of the object (in kilograms)
c = specific heat capacity of the material (in Joules per kilogram per degree Celsius)
delta T = change in temperature (in degrees Celsius)
In this case, we are given the mass of the iron block (m = 2.0 kg), the amount of heat transferred to the atmosphere (Q = 180,000 J), and the initial temperature (350 degrees Celsius).
First, we need to rearrange the equation to solve for delta T:
delta T = Q / (mc)
Now, we can substitute the given values into the equation:
delta T = 180,000 J / (2.0 kg * c)
To find the final temperature, we need to add the change in temperature delta T to the initial temperature:
Final temperature = Initial temperature + delta T
Now, to get the specific heat capacity (c) of iron, we can either look it up or assume it's around 450 J/kg°C.
Substituting this value into the equation, we have:
delta T = 180,000 J / (2.0 kg * 450 J/kg°C)
delta T = 200 °C
Finally, we can calculate the final temperature:
Final temperature = 350°C + 200°C
Final temperature = 550°C
Therefore, the final temperature of the iron block is 550 degrees Celsius.