In Python - A state creates license plates, each containing two letters followed by three digits. The first letter must be a vowel (A,E,I,O,U), and duplicate letters and digits are allowed. The second letter can be any letter of the alphabet. The state only uses capital letters. A sample license plate is: IS-030.

How many different license plates are possible? Have Python answer this question using multiplication and then list on the screen in one column all the possible license plates.
AA-000
AA-001
AA-002, etc.

This is the part that will calculate the total number of license plates possible.

def main():

num_of_poss_plates = 5*26*10*10*10
print('The number of possible plates are: ', num_of_poss_plates)

main()

Do not have Python.

5 * 5 * 10 * 10* 10 = ?

You are right. I did not read the question carefully enough.

It says to list all possible license plates, not the total number.

To find the number of different license plates possible, we can use the concept of multiplication. Since each position on the license plate can have a certain number of options, we can multiply the number of options for each position to calculate the total number of possible combinations.

Let's break it down step by step:

Step 1: Determine the number of options for each position

- The first letter must be a vowel, and there are 5 vowels (A, E, I, O, U), so there are 5 options for the first letter.
- The second letter can be any letter of the alphabet, so there are 26 options for the second letter.
- The third, fourth, and fifth positions are digits, and there are 10 digits (0 to 9), so there are 10 options for each of these positions.

Step 2: Calculate the total number of possible combinations

To find the total number of combinations, we multiply the number of options for each position:

Total combinations = number of options for the first letter * number of options for the second letter * number of options for the third position * number of options for the fourth position * number of options for the fifth position

Total combinations = 5 * 26 * 10 * 10 * 10

Total combinations = 65,000

So, there are 65,000 different license plates possible.

Now let's list all the possible license plates in a column using Python:

```python
vowels = ['A', 'E', 'I', 'O', 'U']
alphabet = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
digits = [str(i).zfill(3) for i in range(1000)] # Generating digits from 000 to 999

license_plates = []

for first_letter in vowels:
for second_letter in alphabet:
for digit in digits:
license_plates.append(f"{first_letter}{second_letter}-{digit}")

for license_plate in license_plates:
print(license_plate)
```

This code generates all the possible combinations and prints them in a column, as requested.