You work with the following system:

2X(g) <---> Y(g)

At, equilibrium, [Y]=3[X]. If K=10, calculate the [Y] at equilibrium.

noob

To calculate the equilibrium concentration of Y, we need to use the equilibrium constant (K) and the concentration of X.

Since K is given as 10 and the equation is set up as:

2X(g) ⇌ Y(g)

We know that the equilibrium expression is:

K = [Y]^1 / [X]^2

Given that [Y] at equilibrium is 3[X], we can substitute these values into the equilibrium expression:

10 = (3[X])^1 / (2X)^2

Simplifying the expression, we have:

10 = 3 / 4X

To solve for X, we can cross-multiply:

10 * 4X = 3

40X = 3

Dividing both sides by 40:

X = 3 / 40

Now that we have the value of X, we can substitute it back into the equation to find [Y]:

[Y] = 3[X]

[Y] = 3 * (3 / 40)

[Y] = 9 / 40

Therefore, the concentration of Y at equilibrium is 9/40.