You work with the following system:
2X(g) <---> Y(g)
At, equilibrium, [Y]=3[X]. If K=10, calculate the [Y] at equilibrium.
noob
To calculate the equilibrium concentration of Y, we need to use the equilibrium constant (K) and the concentration of X.
Since K is given as 10 and the equation is set up as:
2X(g) ⇌ Y(g)
We know that the equilibrium expression is:
K = [Y]^1 / [X]^2
Given that [Y] at equilibrium is 3[X], we can substitute these values into the equilibrium expression:
10 = (3[X])^1 / (2X)^2
Simplifying the expression, we have:
10 = 3 / 4X
To solve for X, we can cross-multiply:
10 * 4X = 3
40X = 3
Dividing both sides by 40:
X = 3 / 40
Now that we have the value of X, we can substitute it back into the equation to find [Y]:
[Y] = 3[X]
[Y] = 3 * (3 / 40)
[Y] = 9 / 40
Therefore, the concentration of Y at equilibrium is 9/40.