Write an equation showing that calcium hydroxide acts as an Arrhenius base in water.
**(I'm not sure where to start or how to go about this question)
To show that calcium hydroxide acts as an Arrhenius base in water, we need to understand what an Arrhenius base is and then write an equation to represent the reaction.
Starting with the definition, an Arrhenius base is a substance that, when dissolved in water, releases hydroxide ions (OH-) as the sole source of hydroxide ions in the solution. In other words, it donates hydroxide ions to the water.
Now let's create the equation:
1. Start with the formula of calcium hydroxide: Ca(OH)2.
2. Write the equation by showing the dissociation of calcium hydroxide in water.
Ca(OH)2 (s) → Ca^2+ (aq) + 2OH- (aq)
In this equation, (s) represents the solid form, and (aq) represents the dissolved ions in the aqueous solution.
By dissociating in water, calcium hydroxide releases hydroxide ions (OH-) into the solution, confirming that it acts as an Arrhenius base.
To show that calcium hydroxide acts as an Arrhenius base in water, we can start by understanding what an Arrhenius base is. According to the Arrhenius concept, a base is a substance that when dissolved in water, increases the concentration of hydroxide ions (OH-) in the solution.
The chemical formula for calcium hydroxide is Ca(OH)2. When it dissolves in water, it dissociates into calcium ions (Ca2+) and hydroxide ions (OH-).
Now, let's write the equation to represent the dissociation of calcium hydroxide in water:
Ca(OH)2 (s) → Ca2+ (aq) + 2OH- (aq)
This equation shows that when calcium hydroxide (Ca(OH)2) solid is added to water, it dissociates into calcium ions (Ca2+) and two hydroxide ions (2OH-) in the aqueous solution.
Therefore, calcium hydroxide acts as an Arrhenius base in water because it increases the concentration of hydroxide ions, which is one of the key characteristics of a base according to the Arrhenius concept.
An Arrhenius base is a compound that provides OH^- when placed in solution.
Ca(OH)2 ==> Ca^2+ + 2OH^-