Solubility of Silver(I) Carbonate is 3.2x10^-2 g/100mL What is the Ksp?
I'm getting 2.19x10^-12
But it's not in the answer sheet
.........Ag2CO3 ==> 2Ag^+ + CO3^2-
I.......solid........0........0
C.......solid........2x.......x
E.......solid........2x.......x
I think you didn't enter the data right. I suspect that is 3.2E-2 g/1000 mL; otherwise, you can't get close to 10^-12 as an answer.
Assuming it is 3.2E-2 g/L, then
3.2E-2/275.75 = about 1.16E-4 M
Ksp = (Ag^+)^2(CO3^2-)
Ksp = (2x)^2(x) = 4x^3
Ksp = 4*(1.16E-4)^3 = about 6.2E-12
The tables give 8.1E-12 which works out to about 0.35E-2 g/L.
To calculate the solubility product constant (Ksp) of a compound, you need to use the given solubility data. In this case, the solubility of Silver(I) Carbonate is 3.2x10^-2 g/100mL.
To determine the Ksp, you need to consider the dissociation of the compound into its ions, which is represented by the following balanced equation:
Ag2CO3(s) ⇌ 2Ag+(aq) + CO32-(aq)
The equilibrium expression for Ksp is defined as the product of the concentrations (raised to the power of their stoichiometric coefficients) of the products, with each concentration raised to the power of its stoichiometric coefficient, divided by the concentration of the reactants:
Ksp = [Ag+]^2 * [CO3^2-]
To calculate the concentrations, you need to convert the given solubility in grams per 100 mL to moles per liter (M). Here's how to do that:
1. Calculate the molar mass of Ag2CO3:
Ag = 107.87 g/mol, C = 12.01 g/mol, O = 16.00 g/mol
Molar mass of Ag2CO3 = (2 * Ag) + C + (3 * O) = (2 * 107.87) + 12.01 + (3 * 16.00) = 275.77 g/mol
2. Convert the given solubility to moles per liter (M):
Solubility of Ag2CO3 = 3.2x10^-2 g/100 mL
= (3.2x10^-2 g) / (275.77 g/mol) * (1000 mL/1 L)
≈ 1.16x10^-4 mol/L
Now, substitute the concentrations into the Ksp expression:
Ksp = [Ag+]^2 * [CO3^2-]
= (2 * 1.16x10^-4)^2 * 1
= 2.69x10^-8
The calculated Ksp value of Silver(I) Carbonate is 2.69x10^-8. Please double-check your calculations to ensure accuracy when comparing it to the given answer on the answer sheet.