In calculating the force of gravity between two objects, if the distance between the objects increased 4 times, the force of gravity will.

A)decrease by 1/16
B)increase by 1/4
C)decrease by 1/4
D)decrease by 4 times

after what I gathered it has to increase but I thought by 4 but that's not a choice so its B, increase by 1/4

The force of attraction between two bodies varies inversely with the square of the distance. If the distance is increased 4 times, the force of attraction between the two bodies decreases by 1/4^2.

ok I misread what I found its 1/16 I understand why and how. thank you

A player kicks a football with an inital velocity of 3.00 m/s at an angle of 60.00 degress above the horizontal distance traveled by the football?

To calculate the force of gravity between two objects, we can use Newton's law of universal gravitation, which states:

F = (G * m1 * m2) / r^2

Where:
- F is the force of gravity
- G is the gravitational constant (a constant value)
- m1 and m2 are the masses of the two objects
- r is the distance between the centers of the two objects.

In this case, the question states that the distance between the two objects increased by 4 times. Let's call the initial distance "r" and the new distance "4r".

If we substitute these new values into the equation, we get:

F' = (G * m1 * m2) / (4r)^2

Simplifying the equation gives:

F' = (G * m1 * m2) / 16r^2

Comparing this to the original equation, we can see that the new force of gravity is 1/16 times the original force:

F' = (1/16) * F

So, the correct answer is A) decrease by 1/16. The force of gravity decreases when the distance between objects increases.