physics

A missile launched at a velocity of 30.0 m/s at an angle of 30.0 to the normal. What is the maximum height the missile attains?

sin 60 = 0.866025404
0.866025404 x 30 = 25.98076211
25.98076211 x 25.98076211 / 2 / 9.8 = 34.4 m

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  1. Did you see the reply on 1 April at 11:44pm about this problem?

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  2. yes but I don't understand I just change the sin 30 to sin 60 like you said

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  3. h = V^2sin^2(µ)/2g

    h = 30^2sin^2(60º)/2(9.8)= 34.4m.

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  4. I am first pasting the previous response. Then, I will step through the steps.
    ---------------
    Break the problem into vertical and horizontal components. Find the initial vertical component (30.0 m/s) * sin(60) because the problem says the missile is launched 30 degress from the NORMAL.
    Determine how long before the vertical velocity is 0. That will be the maximum height. Plug that time into the distance equation:
    t = time
    g=gravity acceleration
    distance = (initial velocity) * t + (1/2)(g)(t^2)
    Remember that for positive up, gravity will be a negative acceleration.
    So, pay attention to the sign of the second term.
    ---------------
    Here is a non-calculus way to solve this.
    First, when the missle is launched it goes up until gravity eventually slows it to a zero vertical speed. That is the maximum height.
    Find the initial vertical velocity.
    (initial vertical velocity) = (initial velocity) * sin(60)
    or
    25.98 m/s = (30.0m/s)*(0.8660
    Now to find how long before the vertical velocity is 0 (of course immediately after that the velocity will be increasing in the DOWN direction).
    The formula for veocity (only using vertical) is:
    velocity = (initial velocity) + (acceleration)*(time)
    use t for time
    We want to know when the velocity is 0.
    0.0 = (25.98 m/s) - (gravity)* t
    The second term is subtracted because the acceleration (gravity) is in the negative direction.
    0.0 = (25.98 m/s) - (9.8 m/s^2)*t
    arranging...
    (9.8 m/s^2)*t = 25.98 m/s
    finally...
    t = 2.651 seconds
    This is the time where the missile will be the highest.
    How high is that?
    A handy distance formula is:
    Here distance is vertical or height.
    height = (initial distance) + (initial velocity) * t) + (0.5)*(g)*(t^2)
    Note the minus sign in the term with gravity.
    height = 0.0m + (25.98 m/s) * t - (0.5)*(9.8 m/s^2)* t^2
    height = (25.98 m/s) * (2.651 s) - (4.9 m/s^2)*(7.028 s^2)
    height = 68.87m - 34.43m
    height = 34.44m

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  5. 34.4m

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