Given that on average, an atom of gold weighs 3.27×10^−22grams, how much
does an Avagadro’s number of gold atoms weigh (take Avagadro’s number to be 6.0221415×10^23).

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asked by Katie
  1. just multiply the mass of each atom by the number of atoms:

    3.27*10^-22 * 6.0221415*10^23 = 19.6924*10^1 = 196.924 g

    check: mol wt of Au is 196.97. Pretty close

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    posted by Steve

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