In two successive chess moves, a player first moves his queen four squares forward, then moves the queen three steps to the left (from the player’s view). Assume each square is 4.0 on a side.
To determine the distance covered by the queen in two successive moves, we can break down the movement into its individual components.
First, the queen moves four squares forward. Since each square has a side length of 4.0, the distance covered in this move is:
4 squares * 4.0 units/square = 16.0 units
Next, the queen moves three steps to the left. Assuming the player's view is from the bottom of the chessboard, the queen moves horizontally. Again, since each square has a side length of 4.0, the distance covered in this move is:
3 squares * 4.0 units/square = 12.0 units
Therefore, in two successive moves, the queen covers a total distance of:
16.0 units + 12.0 units = 28.0 units