In two successive chess moves, a player first moves his queen four squares forward, then moves the queen three steps to the left (from the player’s view). Assume each square is 4.0 on a side.
To find the distance covered by the queen in two successive moves, we can calculate the total displacement by separating the moves into the x-axis and y-axis components.
First, let's consider the first move where the queen moves four squares forward. Each square is 4.0 units on a side, so the displacement along the y-axis (vertical direction) is 4.0 units × 4 squares = 16.0 units.
Next, in the second move, the queen moves three steps to the left. Since each square is 4.0 units on a side, the displacement along the x-axis (horizontal direction) is 4.0 units × 3 squares = 12.0 units.
Therefore, the total distance covered by the queen in the two successive moves is the sum of the displacement along the x-axis and y-axis: 16.0 units + 12.0 units = 28.0 units.
Hence, the queen has covered a total distance of 28.0 units in these two successive chess moves.