A ball is thrown downward with an initial velocity of 11 m/s. Using the approximate value of g = 10 m/s2, what is the velocity of the ball 1.6 seconds after it is released?
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To find the velocity of the ball after 1.6 seconds, we can use the equation of motion for objects falling freely under the influence of gravity:
v = u + gt
Where:
v = final velocity
u = initial velocity
g = acceleration due to gravity
t = time
Given that the initial velocity (u) is 11 m/s, the acceleration due to gravity (g) is 10 m/s², and the time (t) is 1.6 seconds, we can substitute these values into the equation to find the final velocity (v):
v = 11 + 10 * 1.6
Simplifying the equation, we have:
v = 11 + 16
v = 27 m/s
So, the velocity of the ball 1.6 seconds after it is released is approximately 27 m/s.