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a truck is carrying a 2800 kg crate of heavy machinery. if the coefficient of static friction between the crate and the bed of the truck is 0.55, what is the maximum rate the driver can decelerate when coming to a stop in order to avoid crushing the cab with the crate?

THANK YOU. LUV YA

Friction is the force causing the crate to accelerate.

Forcefriction= masscrate*acceleration
mu(masscrate*g)=masscrate(acceleration

solve for acceleration

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asked by tiarra

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