Physics

Suppose the water near the top of Niagara Falls has a horizontal speed of 2.3 m/s just before it cascades over the edge of the falls. At what vertical distance below the edge does the velocity vector of the water point downward at a 55° angle below the horizontal?

I'm not sure what do with the angle.

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asked by Hawkins
  1. That would be where the vertical velocity component Vy is related to the horizontal component Vx by
    Vy/Vx = tan 55 = 1.428
    Vy = 3.285 m/s (downward)
    Calculate how far it must fall (Y) to reach that vertical velcoity component.

    Vy = sqrt(2 g Y) = 3.285 m/s
    2 g Y = 10.79 m^2/s^2
    Y is less than 1 meter!

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    posted by drwls

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