what mass of baking soda would completely react with 3.8 g acetic acid
CH3COOH + NaHCO3 ==> CH3COONa + H2O + CO2
Convert CH3COOH to mols. mols = grams/molar mass.
Convert mols CH3COOH to mols NaHCO3 using the coefficients in the balanced equation.
Convert mols NaHCO3 to grams. g = mols x molar mass.
To determine the mass of baking soda (sodium bicarbonate) that would completely react with 3.8 g of acetic acid, you'll need to balance the chemical equation and apply stoichiometry.
First, let's write the balanced chemical equation for the reaction between acetic acid (CH3COOH) and baking soda (NaHCO3):
CH3COOH + NaHCO3 -> CH3COONa + H2O + CO2
From the balanced equation, we can see that the stoichiometric ratio between acetic acid and baking soda is 1:1. This means that for every 1 mole of acetic acid, 1 mole of baking soda is required to completely react.
Next, we need to convert the mass of acetic acid to moles using its molar mass. The molar mass of acetic acid is 60.05 g/mol:
3.8 g acetic acid / 60.05 g/mol = 0.06328 mol acetic acid
Since the stoichiometry is 1:1, we know that 0.06328 moles of baking soda will completely react with 0.06328 moles of acetic acid.
Finally, we can find the mass of baking soda using its molar mass of 84.01 g/mol:
0.06328 mol baking soda x 84.01 g/mol = 5.31 g baking soda
Therefore, 5.31 grams of baking soda would completely react with 3.8 grams of acetic acid.
To find the mass of baking soda that would completely react with 3.8 g of acetic acid, we need to determine the stoichiometry of the balanced chemical equation between baking soda (sodium bicarbonate, NaHCO3) and acetic acid (CH3COOH).
The balanced chemical equation for the reaction is:
NaHCO3 + CH3COOH -> H2O + CO2 + CH3COONa
From the equation, we can see that one mole of sodium bicarbonate (NaHCO3) reacts with one mole of acetic acid (CH3COOH). We need to convert the mass of acetic acid to moles, and then use the stoichiometric ratio to find the corresponding mass of baking soda.
Step 1: Calculate the moles of acetic acid (CH3COOH)
To calculate the moles of acetic acid, we need to know the molar mass of acetic acid (CH3COOH). The molar mass of carbon (C) is 12.01 g/mol, hydrogen (H) is 1.01 g/mol, and oxygen (O) is 16.00 g/mol.
Molar mass of CH3COOH:
(12.01 * 2) + (1.01 * 4) + (16.00 * 2) + 1.01 = 60.05 g/mol
Now, we can calculate the moles of acetic acid:
moles of CH3COOH = mass of acetic acid / molar mass of CH3COOH
moles of CH3COOH = 3.8 g / 60.05 g/mol
Step 2: Calculate the moles of baking soda (NaHCO3)
Since the balanced equation indicates a 1:1 stoichiometric ratio between acetic acid and baking soda, the number of moles of baking soda will be the same as the number of moles of acetic acid.
moles of NaHCO3 = moles of CH3COOH
Step 3: Calculate the mass of baking soda (NaHCO3)
Now, we can calculate the mass of baking soda using the moles of NaHCO3 and the molar mass of NaHCO3. The molar mass of sodium (Na) is 22.99 g/mol, hydrogen (H) is 1.01 g/mol, carbon (C) is 12.01 g/mol, and oxygen (O) is 16.00 g/mol.
Molar mass of NaHCO3:
22.99 + 1.01 + 12.01 + (16.00 * 3) = 84.01 g/mol
mass of NaHCO3 = moles of NaHCO3 * molar mass of NaHCO3
Now you can substitute the value of moles of NaHCO3 (which is equal to the moles of CH3COOH) into the equation to calculate the mass of baking soda:
mass of NaHCO3 = moles of CH3COOH * molar mass of NaHCO3