(2c+1)(3c+5)
x^2-3x-10
What is your question?
that i don't undestand how you multiply and factor these things.
(2c + 1)(3c + 5)
2c * 3c + 2c * 5 + 1 * 3c + 1 * 5
can you finish this?
x^2 - 3x - 10
(x - 5)(x + 2)
(2c + 1)(3c + 5) =
6c^2+10c+3c+5
6c^2+13c+5
idk how to do this one
factor: 2x^2-7x-15
(x-4)(x+2)
Your answer to the first one is correct.
your answer to 2x^2 -7x - 15 is not correct because if you multiply your factors, you get
x^2 - 2x - 8
(2x + 3)(x - 5)
i don't undertand how you got that how did you get 2 and 8 and then get 3 and 5
You factored the expression 2x^2 - 7x - 15 and got (x - 4)(x + 2)
If you multiply those together, you do not get the original expression. Your answer is not correct.
the factors that have 3 and 5 in them are the correct answer.