A barefoot field-goal kicker imparts a speed of 35 m/s to a football initially at rest. If the football has a mass of 0.39 kg and the time of contact with the ball is 0.038 s, what is the force exerted by the ball on the kicker’s foot?

I tried the formula F=(m(vf-vi))/change in time and got 359.210526316 but this was incorrect.

To find the force exerted by the ball on the kicker's foot, you need to use Newton's second law of motion, which states that force (F) is equal to the change in momentum (Δp) per unit of time (Δt). The formula can be written as:

F = Δp / Δt

In this case, the initial momentum (p_initial) of the football is zero since it is initially at rest. The final momentum (p_final) can be calculated using the equation:

p_final = mass (m) × velocity (v)

Given that the mass of the football is 0.39 kg and the speed imparted to it is 35 m/s, the final momentum is:

p_final = 0.39 kg × 35 m/s = 13.65 kg·m/s

Now, we can calculate the change in momentum (Δp) by subtracting the initial momentum from the final momentum:

Δp = p_final - p_initial = p_final - 0 = p_final

So, Δp = 13.65 kg·m/s.

Lastly, divide the change in momentum by the time of contact (Δt) to find the force:

F = Δp / Δt = 13.65 kg·m/s / 0.038 s

Calculating this equation will give you the correct answer for the force exerted by the ball on the kicker's foot.