How much heat is required to raise the body temperature of a 60.0-kg woman from 37.0° C to 38.2° C?
To calculate the amount of heat required to raise the body temperature of a woman, you can use the formula:
q = m * c * ΔT
where:
q is the heat energy,
m is the mass of the woman,
c is the specific heat capacity of the body, and
ΔT is the change in temperature.
Given information:
Mass of the woman (m) = 60.0 kg
Initial temperature (T1) = 37.0°C
Final temperature (T2) = 38.2°C
To solve the problem, we need to find the value of specific heat capacity (c) for the human body. The specific heat capacity of the human body is approximately 3.5 kJ/kg·°C.
Substitute the values into the formula:
q = m * c * ΔT
q = (60.0 kg) * (3.5 kJ/kg·°C) * (38.2°C - 37.0°C)
Calculating the change in temperature:
ΔT = T2 - T1
ΔT = 38.2°C - 37.0°C
ΔT = 1.2°C
Now, substitute the values into the formula:
q = (60.0 kg) * (3.5 kJ/kg·°C) * (1.2°C)
Calculating the final result:
q = 252 kJ
Therefore, it would require approximately 252 kJ of heat to raise the body temperature of a 60.0-kg woman from 37.0°C to 38.2°C.