If, I ahve a trapezoid with two angles
Angle 86 degrees and 41 degrees and angle A 133 degrees
then,side b 10
Short base 6
How do I solve to get angle B?
The 4 angles of a trapezoid add up to 360.
Since you give the measures of three of those angles, add then subtract to find the fourth angle.
I got 100 degrees for the 4th angle, is this right?
Also, the numbers around the shape I don't do anything for them?
What did you get when you added
86 + 41 + 133?
I got 260 degrees
I understand the degrees problem, but confused on the non degree numbers I mentined above? 10 and 6 around the shape?
Something is wrong with the information you have given us. 100 does make the four angles add up to 360 but each pair of angles between the parallel bases has to add up to 180 and with this information, they do not. Are the parallel bases AB and CD?
AD and BC are parallel
The short base parallel is AD with 6 in the middle, but angle D has 86 degrees.
BC long base paralle has no number but angle c is 41 degrees.
The side leg AB has a number 1o, but A has angle 133 degrees.
Make sense?
AD and BC are parallel
The short base parallel is AD with 6 in the middle, but angle D has 86 degrees.
BC long base paralle has no number but angle c is 41 degrees.
The side leg AB has a number 10.
I took out the 133 degrees on angle A