How many grams of Na2O are produced when 62.5g of Na reacts?
Well, you know what they say - when Na reacts, it's a sodium-ational party! Now, let's do some chemistry calculations, shall we?
The molar mass of Na is 22.99 g/mol, and the molar mass of Na2O is 61.98 g/mol. Since we have 62.5 g of Na, we can use stoichiometry to find the amount of Na2O produced.
Using the ratio of coefficients from the balanced equation, which is 4Na + O2 -> 2Na2O, we know that 4 moles of Na react to produce 2 moles of Na2O.
So, to find the moles of Na, we divide 62.5 g by the molar mass of Na:
62.5 g / 22.99 g/mol ≈ 2.72 moles of Na
Since the mole ratio of Na to Na2O is 4:2, which reduces to 2:1, we know that there will be half as many moles of Na2O as there are moles of Na.
Therefore, we have:
2.72 moles of Na * (1/2) ≈ 1.36 moles of Na2O
Finally, we can find the grams of Na2O by multiplying the moles of Na2O by the molar mass of Na2O:
1.36 moles of Na2O * 61.98 g/mol ≈ 84.31 grams of Na2O
So, after all those calculations, we would expect approximately 84.31 grams of Na2O to be produced. Have fun with your sodium-ational chemistry adventure!
To determine the amount of Na2O produced when 62.5g of Na reacts, we need to use the balanced chemical equation for the reaction. The balanced equation for the reaction between Na and O2 to form Na2O is:
4Na + O2 -> 2Na2O
From the balanced equation, we can see that it takes 4 moles of Na to produce 2 moles of Na2O.
To find the number of moles of Na, we need to divide the mass of Na by its molar mass. The molar mass of Na is 22.99 g/mol.
Number of moles of Na = mass of Na / molar mass of Na
Number of moles of Na = 62.5g / 22.99 g/mol
Now, we can calculate the number of moles of Na2O produced using the mole ratio from the balanced equation.
Number of moles of Na2O = (Number of moles of Na / 4) * 2
Finally, we can convert the number of moles of Na2O to grams using its molar mass. The molar mass of Na2O is 61.98 g/mol.
Mass of Na2O = Number of moles of Na2O * molar mass of Na2O
By substituting the values, we can calculate the grams of Na2O produced when 62.5g of Na reacts.
To find out how many grams of Na2O are produced when 62.5g of Na reacts, we need to determine the balanced chemical equation for the reaction.
The balanced chemical equation for the reaction between Na and O2 to form Na2O is:
4Na + O2 -> 2Na2O
From the balanced chemical equation, we can see that 4 moles of Na react to produce 2 moles of Na2O.
Now, to find the number of moles of Na that reacts, we can use the molar mass of Na, which is 22.99 g/mol.
Moles of Na = Mass of Na / Molar mass of Na
Moles of Na = 62.5 g / 22.99 g/mol
Moles of Na ≈ 2.717 mol
According to the balanced equation, it takes 4 moles of Na to produce 2 moles of Na2O. Therefore, the mole ratio between Na and Na2O is 4:2, or 2:1.
Since we have 2.717 moles of Na, we can use the mole ratio to calculate the moles of Na2O produced:
Moles of Na2O = (2.717 mol Na / 4 mol Na) * 2 mol Na2O
Moles of Na2O ≈ 1.359 mol
Finally, to determine the mass of Na2O produced, we can use the molar mass of Na2O, which is 61.98 g/mol.
Mass of Na2O = Moles of Na2O * Molar mass of Na2O
Mass of Na2O = 1.359 mol * 61.98 g/mol
Mass of Na2O ≈ 84.32 g
Therefore, approximately 84.32 grams of Na2O are produced when 62.5 grams of Na reacts.
4Na + O2 ==> 2Na2O
mols Na = grams/atomic mass.
Convert mols Na to mols Na2O using the coefficients in the balanced equation.
Convert mols Na2O to g. g = g Na2O x molar mass Na2O.