In 1996, NASA performed an experiment called the Tethered Satellite experiment. In this experiment a 2.20 104-m length of wire was let out by the space shuttle Atlantis to generate a motional emf. The shuttle had an orbital speed of 7.50 103 m/s, and the magnitude of the earth's magnetic field at the location of the wire was 4.90 10-5 T. If the wire had moved perpendicular to the earth's magnetic field, what would have been the motional emf generated between the ends of the wire?
What is B*L*V ?
To find the motional emf generated between the ends of the wire, we need to use the formula:
emf = B * v * L
where:
emf is the motional emf,
B is the magnitude of the magnetic field,
v is the velocity of the wire,
L is the length of the wire.
In this case, the magnitude of the magnetic field is given as 4.90 * 10^(-5) T, and the length of the wire is given as 2.20 * 10^4 m.
The velocity of the wire can be calculated using the orbital speed of the space shuttle Atlantis, which is given as 7.50 * 10^3 m/s.
Now we can substitute the values into the formula:
emf = (4.90 * 10^(-5) T) * (7.50 * 10^3 m/s) * (2.20 * 10^4 m)
emf = 8.085 * 10^(-2) V
Therefore, the motional emf generated between the ends of the wire would be approximately 0.08085 V.