Choose the equation that could be used to find three consecutive integers whose sum is 99
What are your choices? What is your answer?
a = first number
b = a + 1 = second number
c = b + 1 = a + 1 + 1 = a + 2 third number
a + b + c = 99
a + a + 1 + a + 2 = 99
3 a + 3 = 99 Subtract 3 to both sides
3 a + 3 - 3 = 99 - 3
3 a = 96 Divide both sides by 3
a = 32
a = first number = 32
b =second number = 32 + 1 = 33
c =third number = 32 + 2 = 34
a + b + c = 32 + 33 + 34 = 99
21
To find three consecutive integers whose sum is 99, we can set up an equation.
Let's represent the first integer as "x". Since the integers are consecutive, we can represent the second integer as "x + 1", and the third integer as "x + 2".
The sum of these three consecutive integers is 99, so we can write the equation as:
x + (x + 1) + (x + 2) = 99
Now, we can solve this equation to find the value of "x":
3x + 3 = 99
Subtracting 3 from both sides:
3x = 96
Dividing both sides by 3:
x = 32
Therefore, the first consecutive integer is 32. By adding 1 and 2 to this, we can find the second and third integers. The three consecutive integers whose sum is 99 are 32, 33, and 34.