if the last digit of a weight measurement is equally likely to be any of the digits 0 through to 9.what is the probability that the last digit is greater than or equal to 5 ?
of the 10 possible digits, how many are >= 5?
To find the probability that the last digit of a weight measurement is greater than or equal to 5, we need to determine how many favorable outcomes there are out of the total possible outcomes.
Since the last digit can be any digit from 0 to 9, there are a total of 10 possible outcomes for the last digit.
Out of these 10 possible outcomes, there are 5 favorable outcomes where the last digit is greater than or equal to 5 (namely 5, 6, 7, 8, and 9).
Therefore, the probability that the last digit is greater than or equal to 5 is given by:
Probability = Number of favorable outcomes / Total number of possible outcomes
= 5 / 10
= 1/2
= 0.5
So, the probability that the last digit is greater than or equal to 5 is 0.5 or 50%.
To calculate the probability that the last digit of a weight measurement is greater than or equal to 5, we first need to determine the total number of possible outcomes.
In this case, the last digit can be any of the digits from 0 to 9, so there are 10 possible outcomes for the last digit.
Next, we need to determine the favorable outcomes, i.e., the number of digits that are greater than or equal to 5. In this case, the digits greater than or equal to 5 are 5, 6, 7, 8, and 9. There are 5 favorable outcomes.
Finally, we can calculate the probability by dividing the number of favorable outcomes by the total number of possible outcomes:
Probability = Number of favorable outcomes / Total number of possible outcomes
Probability = 5/10
Therefore, the probability that the last digit of a weight measurement is greater than or equal to 5 is 0.5 or 50%.