three of four numbers have a sum of 22. if the average of the four number is 8, what is the four number
2+4+8=16+6=22 the answer is 6
Did you solve this algebraically?
It appears that 6 satisfies the conditions given.
To solve this problem, let's represent the four numbers as A, B, C, and D. We know that the average of the four numbers is 8. Hence,
(A + B + C + D) / 4 = 8
We are also given that the sum of three of the numbers is 22. Let's assume that A, B, and C are the three numbers whose sum is 22. Therefore,
A + B + C = 22
To find the value of D, we can rearrange the first equation to solve for the sum of the four numbers:
A + B + C + D = 8 * 4
A + B + C + D = 32
Now, we have two equations:
A + B + C = 22
A + B + C + D = 32
By subtracting the first equation from the second, we can eliminate (A + B + C) and find the value of D:
(A + B + C + D) - (A + B + C) = 32 - 22
D = 10
Therefore, the four numbers are A, B, C, and D, where D equals 10. The values of A, B, and C cannot be determined from the given information.